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取り合えず、彼女を晒す

$\left\{\begin{array}{l}
n!\simeq\sqrt{2n\pi}\left(\dfrac{n}{e}\right)^n\\
n!\simeq\sqrt{2n\pi}\left(\dfrac{n}{e}\right)^n\left(1+\dfrac{1}{12n}\right)
\end{array}\right.$

下の方がより近いのだが、一目惚れしたのは前者です

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